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Re: Weight of CO2: "Rogue National Park" Deletes Tweets After Defying Trump 

By: Decomposed in POPE IV | Recommend this post (1)
Thu, 26 Jan 17 1:59 AM | 40 view(s)
Boardmark this board | POPES NEW and Improved Real Board 		Msg. 19002 of 47202
(This msg. is a reply to 18994 by monkeytrots)
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mt: 

re: "Carbon - MW=12 (mw=molecular weight)
Oxygen - MW=16"

Right you are. I think I said oxygen's weight was 15. My bad. The memory ain't what it used to be.

You've listed the ATOMIC weights, not the MOLECULAR weights, of oxygen and carbon. Oxygen usually pairs up, so its molecular weight would be 32.

CARBON exists in many forms - C2, C3, C4, etc. so I don't see how the term "MOLECULAR WEIGHT" could even apply to it.
 




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Re: Weight of CO2: "Rogue National Park" Deletes Tweets After Defying Trump
By: monkeytrots in POPE IV
Thu, 26 Jan 17 12:35 AM 		Msg. 18994 of 47202

Micro -
Carbon - MW=12 (mw=molecular weight)
Oxygen - MW=16

C02- MW=44 (12+32)

Thus: 1 lb carbon yeilds 1* (44/12) = 3.6 lbs. of CO2

If, and only if, gasoline were 100% octane - percent of Carbon per gallon of gas is derived from:
octane is C8H18 MW of C=96, H=18 total=114)

then:

6.2 lbs of gas = 6.2* (96/114) == 5.221 lbs of C

5.221 lbs of C yields => 5.221 * (44/12) = 19.14 lbs of CO2

With 100% combustion efficiency (ie. no CO produced), which, of course, never happens.

Just file this in the fwiw compartment.

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