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Re: Weight of CO2: "Rogue National Park" Deletes Tweets After Defying Trump

By: monkeytrots in POPE IV | Recommend this post (0)
Thu, 26 Jan 17 12:35 AM | 51 view(s)
Boardmark this board | POPES NEW and Improved Real Board 		Msg. 18994 of 47202
(This msg. is a reply to 18985 by micro)
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Micro -
Carbon - MW=12 (mw=molecular weight)
Oxygen - MW=16

C02- MW=44 (12+32)

Thus: 1 lb carbon yeilds 1* (44/12) = 3.6 lbs. of CO2

If, and only if, gasoline were 100% octane - percent of Carbon per gallon of gas is derived from:
octane is C8H18 MW of C=96, H=18 total=114)

then:

6.2 lbs of gas = 6.2* (96/114) == 5.221 lbs of C

5.221 lbs of C yields => 5.221 * (44/12) = 19.14 lbs of CO2

With 100% combustion efficiency (ie. no CO produced), which, of course, never happens.

Just file this in the fwiw compartment.





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The above is a reply to the following message:
Re: "Rogue National Park" Deletes Tweets After Defying Trump
By: micro in POPE IV
Wed, 25 Jan 17 10:38 PM 		Msg. 18985 of 47202

This is incredulous.

"Burning one gallon of gasoline puts nearly 20lbs of carbon dioxide into our atmosphere. #climate"

Here is exactly why what these PROPOGANDISTS cannot possibly be believed.

Let's do some simple math.

ONE GALLON of water weight 8.33 pounds. ONE gallon of gasoline weighs 6.2 pounds.

HOW, after one gallon in RAW FORM of gas is BURNED, which weighed only 8.33 pounds to begin with, possibly add 20 pounds of carbon dioxide to the atmosphere????

Let's see. HMMMMMMMMMM.

SOmething that weighs 6.2 pounds is burned, consumed completely by fire, and yet we are to believe that the off gassing will somehow weigh 20 pounds in carbon dioxide....


YEP. I always knew these people were screwballs and just plain STUPID, but this really demonstrates it well.

If people just did not know how much a gallon of gas weighed they might have been able to pull off this bunch of magic to support their NON-provable claim.....

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