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Re: The Square-Cube law........

By: Cactus Flower in ALEA | Recommend this post (0)
Tue, 24 Jun 14 4:03 AM | 21 view(s)
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Msg. 15731 of 54959
(This msg. is a reply to 15730 by Cactus Flower)

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But I think the relationship between velocity and thrust isn't linear.

So I am not sure what portion of an aircraft's thrust a 62% velocity relationship represents.




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The above is a reply to the following message:
Re: The Square-Cube law........
By: Cactus Flower
in ALEA
Tue, 24 Jun 14 3:50 AM
Msg. 15730 of 54959

"So you are saying that at 0.53 Max Mach operating
the Engine is only operating at less than 40% or
so max thrust/Power,it has 60% more Power
available in reserve,50% odd more it is rated for."

The relationship between 0.53 mach and 0.86 mach is 62%.

How do you derive your "less than 40%"?

Again, you are measuring engine thrust when operating velocities have nothing to do with engine capability. Operating velocities are defined according to long run wear and tear requirements and passenger safety.

You are flying around the same circle as if it takes the conversation somewhere. An aircraft's MOV is the maximum speed an aircraft is able to fly in order to minimize maintenance costs. It isn't a useable multiplier for an aircraft engine's potential thrust.


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